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	<title>Lotusland of Mathematical Dreams</title>
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	<description>wake up to a phantasmagoria</description>
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		<title>Lotusland of Mathematical Dreams</title>
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		<title>Random Question (1)</title>
		<link>http://jagadeeshbp.wordpress.com/2009/10/25/random-question-1/</link>
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		<pubDate>Sun, 25 Oct 2009 09:10:19 +0000</pubDate>
		<dc:creator>jagadeeshbp</dc:creator>
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		<category><![CDATA[algorithms]]></category>
		<category><![CDATA[computational complexity]]></category>

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		<description><![CDATA[Are there transformers for P problems, like SAT in NP-Complete? For all problems X in P, there&#8217;s a single problem Y s.t. Y  is polynomial time reducible to X?
       <img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=jagadeeshbp.wordpress.com&blog=926637&post=28&subd=jagadeeshbp&ref=&feed=1" />]]></description>
			<content:encoded><![CDATA[<div class='snap_preview'><br /><p>Are there transformers for P problems, like SAT in NP-Complete? For all problems X in P, there&#8217;s a single problem Y s.t. Y  is polynomial time reducible to X?</p>
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		<title>P=NP and Erik Demaine of MIT</title>
		<link>http://jagadeeshbp.wordpress.com/2009/04/27/pnp-and-erik-demaine-of-mit/</link>
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		<pubDate>Mon, 27 Apr 2009 10:54:05 +0000</pubDate>
		<dc:creator>jagadeeshbp</dc:creator>
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		<category><![CDATA[computer science]]></category>
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		<description><![CDATA[
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			<content:encoded><![CDATA[<div class='snap_preview'><br /><p><span style="text-align:center; display: block;"><a href="http://jagadeeshbp.wordpress.com/2009/04/27/pnp-and-erik-demaine-of-mit/"><img src="http://img.youtube.com/vi/VqeF98GGiXQ/2.jpg" alt="" /></a></span></p>
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		<title>Revisiting Algorithm Analysis</title>
		<link>http://jagadeeshbp.wordpress.com/2009/04/24/revisiting-algorithm-analysis/</link>
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		<pubDate>Fri, 24 Apr 2009 11:25:26 +0000</pubDate>
		<dc:creator>jagadeeshbp</dc:creator>
				<category><![CDATA[Uncategorized]]></category>
		<category><![CDATA[algorithms]]></category>
		<category><![CDATA[Big O]]></category>
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		<description><![CDATA[Yet again, another subject that I dreaded due to the incomprehensible and intangible approach in which the subject was taught. One fundamental question I had was, knowing the definition of Big O notation, what does  really mean?
Let me try to put them in my perspective. Think that I am planning to go and buy [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=jagadeeshbp.wordpress.com&blog=926637&post=12&subd=jagadeeshbp&ref=&feed=1" />]]></description>
			<content:encoded><![CDATA[<div class='snap_preview'><br /><p>Yet again, another subject that I dreaded due to the incomprehensible and intangible approach in which the subject was taught. One fundamental question I had was, knowing the definition of Big O notation, what does <img src='http://s3.wordpress.com/latex.php?latex=O%28f%28n%29%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='O(f(n))' title='O(f(n))' class='latex' /> really mean?</p>
<p>Let me try to put them in my perspective. Think that I am planning to go and buy a new shirt and I do not know what its exact cost is. But to make sure that I have enough money to buy one, I kind of predict, it would cost at the maximum of say a $1000 (I would love it as a gift, better). That is sort of the upper bound. I know that the cost will not go beyond that; even in the worst case.</p>
<p>Big O notation is similar to that. It defines an upperbound to the complexity of the function. Consider the case of sorting <img src='http://s1.wordpress.com/latex.php?latex=n&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='n' title='n' class='latex' /> elements, the time taken (considering time complexity, we can worry about space complexity some other time) is given by the function <img src='http://s2.wordpress.com/latex.php?latex=f%28n%29+%3D+n%5E3%2Bn%5E2%2B1&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='f(n) = n^3+n^2+1' title='f(n) = n^3+n^2+1' class='latex' />. By the definition of Big O, the upper bound is <img src='http://s3.wordpress.com/latex.php?latex=O%28f%28n%29%29+%3D+n%5E3&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='O(f(n)) = n^3' title='O(f(n)) = n^3' class='latex' />. We can get this by removing all constants, and lower order terms, leaving us with just <img src='http://s1.wordpress.com/latex.php?latex=n%5E3&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='n^3' title='n^3' class='latex' />.</p>
<p>By definition, <img src='http://s2.wordpress.com/latex.php?latex=f%28n%29+%3D+O%28g%28n%29%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='f(n) = O(g(n))' title='f(n) = O(g(n))' class='latex' /> means that for some constants <img src='http://s3.wordpress.com/latex.php?latex=n_0%3E0&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='n_0&gt;0' title='n_0&gt;0' class='latex' /> and <img src='http://s1.wordpress.com/latex.php?latex=C%3E0&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='C&gt;0' title='C&gt;0' class='latex' />, <img src='http://s2.wordpress.com/latex.php?latex=0+leq+f%28n%29+leq+C.g%28n%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='0 leq f(n) leq C.g(n)' title='0 leq f(n) leq C.g(n)' class='latex' />, <img src='http://s3.wordpress.com/latex.php?latex=forall+n+geq+n_0&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='forall n geq n_0' title='forall n geq n_0' class='latex' /></p>
<p>Let us try to interpret this. <img src='http://s1.wordpress.com/latex.php?latex=0leq+f%28n%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='0leq f(n)' title='0leq f(n)' class='latex' /> part means that we are considering the positive values of <img src='http://s2.wordpress.com/latex.php?latex=f%28n%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='f(n)' title='f(n)' class='latex' />.</p>
<p>Following shows how the graphs of the functions <img src='http://s3.wordpress.com/latex.php?latex=f%28x%29+%3D+x%5E3%2Bx%5E2%2B14&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='f(x) = x^3+x^2+14' title='f(x) = x^3+x^2+14' class='latex' />, <img src='http://s1.wordpress.com/latex.php?latex=f%28x%29+%3D+x%5E3&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='f(x) = x^3' title='f(x) = x^3' class='latex' /> and <img src='http://s2.wordpress.com/latex.php?latex=f%28x%29+%3D+2.x%5E3&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='f(x) = 2.x^3' title='f(x) = 2.x^3' class='latex' /> looks like.<br />
<img src="http://i170.photobucket.com/albums/u279/jagxkool/graphs-1.jpg" alt="" /><br />
It is can be seen that <img src='http://s3.wordpress.com/latex.php?latex=f%28x%29+%3D+2.x%5E3&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='f(x) = 2.x^3' title='f(x) = 2.x^3' class='latex' /> is above <img src='http://s1.wordpress.com/latex.php?latex=f%28n%29+%3D+x%5E3%2Bx%5E2%2B1+forall+x+ge+0&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='f(n) = x^3+x^2+1 forall x ge 0' title='f(n) = x^3+x^2+1 forall x ge 0' class='latex' />.</p>
<p>So we have for <img src='http://s2.wordpress.com/latex.php?latex=f%28n%29+%3D+n%5E3%2Bn%5E2%2B1&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='f(n) = n^3+n^2+1' title='f(n) = n^3+n^2+1' class='latex' />,<br />
<img src='http://s3.wordpress.com/latex.php?latex=O%28f%28n%29+%3D+g%28n%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='O(f(n) = g(n)' title='O(f(n) = g(n)' class='latex' />, where <img src='http://s1.wordpress.com/latex.php?latex=g%28n%29+%3D+n%5E3%2C+C+%3D+2+and+n_0+%3D+0&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='g(n) = n^3, C = 2 and n_0 = 0' title='g(n) = n^3, C = 2 and n_0 = 0' class='latex' />.</p>
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		<title>Taylor&#8217;s Formula</title>
		<link>http://jagadeeshbp.wordpress.com/2007/11/14/taylors-formula/</link>
		<comments>http://jagadeeshbp.wordpress.com/2007/11/14/taylors-formula/#comments</comments>
		<pubDate>Wed, 14 Nov 2007 04:48:20 +0000</pubDate>
		<dc:creator>jagadeeshbp</dc:creator>
				<category><![CDATA[Uncategorized]]></category>

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		<description><![CDATA[Let  be a function continous over the closed interval, [] such that has  derivative, which is written as ; then:

PROOF:
Let

Also,

Consider a polynomial,

We can see that,

Similarly,

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			<content:encoded><![CDATA[<div class='snap_preview'><br /><p>Let <img src='http://s1.wordpress.com/latex.php?latex=f%28x%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='f(x)' title='f(x)' class='latex' /> be a function continous over the closed interval, [<img src='http://s2.wordpress.com/latex.php?latex=a%2Cb&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='a,b' title='a,b' class='latex' />] such that<img src='http://s3.wordpress.com/latex.php?latex=f%28x%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='f(x)' title='f(x)' class='latex' /> has <img src='http://s1.wordpress.com/latex.php?latex=%28n%2B1%29%5E%7Bth%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='(n+1)^{th}' title='(n+1)^{th}' class='latex' /> derivative, which is written as <img src='http://s2.wordpress.com/latex.php?latex=f%5E%7B%28n%2B1%29%7D%28x%29&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='f^{(n+1)}(x)' title='f^{(n+1)}(x)' class='latex' />; then:</p>
<p><img src='http://s3.wordpress.com/latex.php?latex=f%28b%29+%3D+f%28a%29+%2B+f%27%28a%29+%28b-a%29+%2B+...+%2B+%5Cfrac%7Bf%5E%7B%28n%29%7D%28a%29%7D%7Bn%21%7D+%28b-a%29%5En+%2B+%5Cfrac%7Bf%5E%7B%28n%2B1%29%7D%28z%29%7D%7B%28n%2B1%29%21%7D+%28b-a%29%5E%7B%28n%2B1%29%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='f(b) = f(a) + f&#039;(a) (b-a) + ... + \frac{f^{(n)}(a)}{n!} (b-a)^n + \frac{f^{(n+1)}(z)}{(n+1)!} (b-a)^{(n+1)}' title='f(b) = f(a) + f&#039;(a) (b-a) + ... + \frac{f^{(n)}(a)}{n!} (b-a)^n + \frac{f^{(n+1)}(z)}{(n+1)!} (b-a)^{(n+1)}' class='latex' /></p>
<p>PROOF:</p>
<p>Let</p>
<p><img src='http://s1.wordpress.com/latex.php?latex=H+%3D+f%28b%29+-+f%28a%29+-+f%27%28a%29+%28b-a%29+-+..+-+%5Cfrac%7Bf%5E%7B%28n%29%7D%28a%29+%7D%7Bn%21%7D%28b-a%29%5En&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='H = f(b) - f(a) - f&#039;(a) (b-a) - .. - \frac{f^{(n)}(a) }{n!}(b-a)^n' title='H = f(b) - f(a) - f&#039;(a) (b-a) - .. - \frac{f^{(n)}(a) }{n!}(b-a)^n' class='latex' /></p>
<p>Also,</p>
<p><img src='http://s2.wordpress.com/latex.php?latex=K+%3D+%5Cfrac%7BH%7D%7B%28b-a%29%5E%28n%2B1%29%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='K = \frac{H}{(b-a)^(n+1)}' title='K = \frac{H}{(b-a)^(n+1)}' class='latex' /></p>
<p>Consider a polynomial,</p>
<p><img src='http://s3.wordpress.com/latex.php?latex=g%28x%29+%3D+f%28b%29+-+f%28x%29+-+f%27%28x%29%28b-x%29+-+f%27%27%28x%29%28b-x%29%5E2...+-+%5Cfrac%7Bf%5E%7B%28n%29%7D%28x%29%7D%7Bn%21%7D%28b-x%29%5En+-+K%28b-x%29%5E%7Bn%2B1%7D&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='g(x) = f(b) - f(x) - f&#039;(x)(b-x) - f&#039;&#039;(x)(b-x)^2... - \frac{f^{(n)}(x)}{n!}(b-x)^n - K(b-x)^{n+1}' title='g(x) = f(b) - f(x) - f&#039;(x)(b-x) - f&#039;&#039;(x)(b-x)^2... - \frac{f^{(n)}(x)}{n!}(b-x)^n - K(b-x)^{n+1}' class='latex' /></p>
<p>We can see that,</p>
<p><img src='http://s1.wordpress.com/latex.php?latex=g%28a%29+%3D+H+-+K%28b-a%29%5E%7Bn%2B1%7D+%3D+0&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='g(a) = H - K(b-a)^{n+1} = 0' title='g(a) = H - K(b-a)^{n+1} = 0' class='latex' /></p>
<p>Similarly,</p>
<p><img src='http://s2.wordpress.com/latex.php?latex=g%28b%29+%3D+f%28b%29+-+f%28b%29+-+f%27%28b%29%28b-b%29+-+...+-+%5Cfrac%7Bf%5E%7B%28n%29%7D%28b%29+%7D%7Bn%21%7D%28b-b%29%5E%7Bn%7D+-+K%28b-b%29%5E%7Bn%2B1%7D+%3D+0&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='g(b) = f(b) - f(b) - f&#039;(b)(b-b) - ... - \frac{f^{(n)}(b) }{n!}(b-b)^{n} - K(b-b)^{n+1} = 0' title='g(b) = f(b) - f(b) - f&#039;(b)(b-b) - ... - \frac{f^{(n)}(b) }{n!}(b-b)^{n} - K(b-b)^{n+1} = 0' class='latex' /></p>
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		<title>Fuzzy Logic</title>
		<link>http://jagadeeshbp.wordpress.com/2007/04/10/fuzzy-logic/</link>
		<comments>http://jagadeeshbp.wordpress.com/2007/04/10/fuzzy-logic/#comments</comments>
		<pubDate>Tue, 10 Apr 2007 11:09:26 +0000</pubDate>
		<dc:creator>jagadeeshbp</dc:creator>
				<category><![CDATA[Uncategorized]]></category>

		<guid isPermaLink="false">http://jagadeeshbp.wordpress.com/2007/04/10/fuzzy-logic/</guid>
		<description><![CDATA[This was one subject which kept haunting me through out the engineering curriculum. Not only was that my ma&#8217;am, teaching the subject, make any sense; but also, the text book, reminded me more of heiroglyphics.
Life went on smoothly, after some how I managed to pass the paper. Finally a job demanded me to shift to [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=jagadeeshbp.wordpress.com&blog=926637&post=7&subd=jagadeeshbp&ref=&feed=1" />]]></description>
			<content:encoded><![CDATA[<div class='snap_preview'><br /><p>This was one subject which kept haunting me through out the engineering curriculum. Not only was that my ma&#8217;am, teaching the subject, make any sense; but also, the text book, reminded me more of heiroglyphics.</p>
<p>Life went on smoothly, after some how I managed to pass the paper. Finally a job demanded me to shift to a far off place, requiring me to take care of myself.  Its all easy I thought. All except a single job, washing. I hated washing. So I decided to buy one of the best washing machines around (all that my pocket could afford, though).</p>
<p>Seeing me, the shop keeper greeted me so well. I threw at him all my requirements. So he showed me a beautiful washing machine (which I hope works). It had a lot of features, gratifying the needs of the lazy soul inside me. He said it had an additional feature, it can automatically decide on the amount of water, detergent and all such inputs required, which is supported by fuzzy logic. Think of the devil, and here comes the devil himself. This theory, has decided with whatever mind it had, not to leave me alone, till my grave may be.</p>
<p>Even my shopkeeper keeps talking about fuzzy logic and its uses. The engineer inside me got hurt a lot. So a decision came to browse through a couple of pages on the web till I can spell the word fuzzy logic in a proper way.</p>
<p>I am now in my office. Is this sentance true. It is true if I am inside the office. It is false if I am outside the office. So what will happen if I am at the gate. It is partly true and partly false. Just like a half full glass is half empty too.</p>
<p>In normal, classic logic, every statement, proposition, has a value of 0 or 1, depending on it is true or false. So in a situation like the one mentioned previously, we cant assign a proper value like this. The value is 0.5 in that case.</p>
<p>Now, think of a statement P. Its truth value assignment is p. p=1 means the statement is true. p=0 means the statement is false. Here comes fun, think of those paradox that your friends used to bombard you with. Think, of a statement like, &#8220;this statement is false&#8221;.</p>
<p>Let&#8217;s call that statement P. Its truth value is p. The truth value for the converse of P (i.e. Not-P) is (1-p). The statement says, in words, that the truth value of P is (1-p).  This means if p=0, p becomes (1-0) =1 and if p=1, (1-p) gives 0. So the value of p keeps oscillating. The only case where this becomes true is when p=0.5. That is permissible with fuzzy logic.</p>
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		<title>Euclidean Postulates</title>
		<link>http://jagadeeshbp.wordpress.com/2007/03/30/euclidean-postulates/</link>
		<comments>http://jagadeeshbp.wordpress.com/2007/03/30/euclidean-postulates/#comments</comments>
		<pubDate>Fri, 30 Mar 2007 10:17:07 +0000</pubDate>
		<dc:creator>jagadeeshbp</dc:creator>
				<category><![CDATA[Mathematics]]></category>
		<category><![CDATA[The Road to Reality]]></category>

		<guid isPermaLink="false">http://jagadeeshbp.wordpress.com/2007/03/30/euclidean-postulates/</guid>
		<description><![CDATA[1. There is a unique straight line segment connecting any two points
2. Unlimited (continuous) extendability of any straight line segment .
3. Existence of a circle with any center and any value for radius .
4. Equality of right angles.
5. If two straight line segments, a and b in a plane intersect another straight line c such [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=jagadeeshbp.wordpress.com&blog=926637&post=6&subd=jagadeeshbp&ref=&feed=1" />]]></description>
			<content:encoded><![CDATA[<div class='snap_preview'><br /><p>1. There is a unique straight line segment connecting any two points</p>
<p>2. Unlimited (continuous) extendability of any straight line segment .</p>
<p>3. Existence of a circle with any center and any value for radius .</p>
<p>4. Equality of right angles.</p>
<p>5. If two straight line segments, a and b in a plane intersect another straight line c such that the sum of the interior angles on the same side of c is less than two right angles, then a and b, extended far enough on that side of c, will intersect somewhere.</p>
<p><a href="http://en.wikipedia.org/wiki/John_Playfair" title="John Playfair on Wikipedia">Playfair</a>&#8217;s Axiom is an alternate variation of the 5th Euclidean postulate (parallel postulate).  It states that for any line and any point that is not on the line, there is a unique straight line through the point which is parallel to the line.</p>
<p><a href="http://en.wikipedia.org/wiki/Parallel_postulate" title="Parallel postulate on Wikipedia" target="_blank">Parallel postulate</a> has a lot of story attached to it. History says of a lot of people who tried to make the fifth postulate a theorem, derivable from the rest four. But finally Beltrami proved the independence of 5th postulate from others.</p>
<p>Remarkable is the effort by <a href="http://http://en.wikipedia.org/wiki/Girolamo_Saccheri" title="Saccheri on Wikipedia" target="_blank">Saccheri</a>, which speaks of the origins of elliptic geometry and hyperbolic geometry.</p>
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		<title>Beltrami Geometry (Stereographic Projection)</title>
		<link>http://jagadeeshbp.wordpress.com/2007/03/30/beltrami-geometry-stereographic-projection/</link>
		<comments>http://jagadeeshbp.wordpress.com/2007/03/30/beltrami-geometry-stereographic-projection/#comments</comments>
		<pubDate>Fri, 30 Mar 2007 08:56:50 +0000</pubDate>
		<dc:creator>jagadeeshbp</dc:creator>
				<category><![CDATA[Mathematics]]></category>
		<category><![CDATA[The Road to Reality]]></category>

		<guid isPermaLink="false">http://jagadeeshbp.wordpress.com/2007/03/30/beltrami-geometry-stereographic-projection/</guid>
		<description><![CDATA[This is an alternate representaion for Hyperbolic geometry. Wikipedia says that this done by projecting a point on a sphere onto a plane tangential to the sphere at the point antinodal to the center of projection (that is the point diametrically opposite to the center of projection).
With this projection, any circle that crosses through the [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=jagadeeshbp.wordpress.com&blog=926637&post=5&subd=jagadeeshbp&ref=&feed=1" />]]></description>
			<content:encoded><![CDATA[<div class='snap_preview'><br /><p>This is an alternate representaion for Hyperbolic geometry. <a href="http://en.wikipedia.org/wiki/Stereographic_projection" title="Stereographic projection on Wikipedia" target="_blank">Wikipedia</a> says that this done by projecting a point on a sphere onto a plane tangential to the sphere at the point antinodal to the center of projection (that is the point diametrically opposite to the center of projection).</p>
<p>With this projection, any circle that crosses through the center of projection becomes a straight line.Any other circle (that does not touch center of projection), can become circles (possibly ellipses in the case of inclined circles).</p>
<p>For an example, think that we are projecting Earth. The center of projection is absolute North Pole. The plane of projection is parallel to the equitorial circle. Now consider the projection of a longitude. It will be a straight line.</p>
<p>Consider the case of a latitude. This becomes a circle. An extreme case will be the equator. It will be a bounding circle.  It is called primitive of the projection. Any other latitude becomes a circle concentric to the primitive and inside it. Infact those latitudes in southern hemisphere will have projection with radius greater than the primitive (Still haven&#8217;t figured out how).</p>
<p>A beautiful description is also available from <a href="http://www.iucr.org/iucr-top/comm/cteach/pamphlets/11/11.html" title="Stereographic projection">International Union of Crystallography</a>. Stereography is used in crystallography it explains.</p>
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		<title>Hyperbolic Geometry</title>
		<link>http://jagadeeshbp.wordpress.com/2007/03/29/hello-world/</link>
		<comments>http://jagadeeshbp.wordpress.com/2007/03/29/hello-world/#comments</comments>
		<pubDate>Thu, 29 Mar 2007 07:11:12 +0000</pubDate>
		<dc:creator>jagadeeshbp</dc:creator>
				<category><![CDATA[Mathematics]]></category>
		<category><![CDATA[The Road to Reality]]></category>

		<guid isPermaLink="false"></guid>
		<description><![CDATA[
What happens when sum of all angles of a triangle is not . Is it possible? Can the area of a triangle be the sum of all its angles? Can a straight line be curved?
If the mind says, no. Its wrong. It is possible. Beyond the Euclidean geometry that we are used to though. The [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=jagadeeshbp.wordpress.com&blog=926637&post=1&subd=jagadeeshbp&ref=&feed=1" />]]></description>
			<content:encoded><![CDATA[<div class='snap_preview'><br /><p align="center"><a href="http://jagadeeshbp.files.wordpress.com/2007/03/hyperbolictessellation_1000.gif" title="hyperbolictessellation_1000.gif"><img src="http://jagadeeshbp.files.wordpress.com/2007/03/hyperbolictessellation_1000.thumbnail.gif" alt="hyperbolictessellation_1000.gif" align="right" /></a></p>
<p>What happens when sum of all angles of a triangle is not <img src='http://s1.wordpress.com/latex.php?latex=180%5E%5Ccirc&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='180^\circ' title='180^\circ' class='latex' />. Is it possible? Can the area of a triangle be the sum of all its angles? Can a straight line be curved?</p>
<p align="left">If the mind says, no. Its wrong. It is possible. Beyond the Euclidean geometry that we are used to though. The case is totally different with <a href="http://en.wikipedia.org/wiki/Hyperbolic_geometry" title="Hyperbolic Geometry on Wikipedia">Hyperbolic spaces</a>.</p>
<p align="left">&nbsp;</p>
<p align="left">&nbsp;</p>
<p align="left">Think of a line drawn on a sphere, a straight line. There is no doubt that the line is perfectly straight. But when you see the line after drawing it, you can feel the curve in the line. The curvature is attributed to the spherical surface. So if you accept the curvature, or rather think of such a line on earth, the curvature is so big that we feel the plane as prefectly flat. So the line becomes perfectly straight. Thus it is the preception that makes the line straight or curved. Hyperbolic geometry is on a spherical universe. So when we try to see it in the Euclidean space, we get confused. We start thinking if the straight line is actually straight or not.</p>
<p align="left">&nbsp;</p>
<p align="left"> Now think of a sphere. A triangle is drawn on it. The projection is taken onto 2-d plane. The bounding circle will be the projection of the equator (actually this is one of the formal representation method for Hyperbolic geometry, called <span class="nowrap"><a href="http://mathworld.wolfram.com/PoincareHyperbolicDisk.html" target="_blank" title="Poincare Hyperbolic Disk Representaion"><em>Poincaré Hyperbolic Disk</em></a>)</span>. The lines under this representation will be straight only if it is a diameter to the circle. With such a representaion, the angle doesnt always sum upto <img src='http://s2.wordpress.com/latex.php?latex=180%5E%5Ccirc&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='180^\circ' title='180^\circ' class='latex' />, as it normally does. It falls short, and by how much depends on the area of the triangle.</p>
<p align="left"><img src='http://s3.wordpress.com/latex.php?latex=%5Calpha%2B%5Cbeta%2B%5Cgamma+%3D+C%5CDelta&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='\alpha+\beta+\gamma = C\Delta' title='\alpha+\beta+\gamma = C\Delta' class='latex' /></p>
<p align="left">Taking the constant C=1, we have the formula for the angle.</p>
<p> Yet again, this is not inside the universe of Hyperbolic geometry. Taking a triangle in a hyperbolic space, and trying to represent it in Euclidean one gives us this pain. There are alternate representations available, which keeps the lines straight, and angles add to <img src='http://s1.wordpress.com/latex.php?latex=180%5E%5Ccirc&#038;bg=ffffff&#038;fg=000000&#038;s=0' alt='180^\circ' title='180^\circ' class='latex' />. But these add in other types of complications. It is even said that an equation for the distance between two points gets more complex this way.</p>
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